Question

Sa se determine media proportionala a numerelor a=3√3 si b=9√3

Answer 1

m g=√3√3×9√3= √3×9×3=√81=9

Answer 2

Media proportionala = media geometrica
mg = $\sqrt{3 \sqrt{3} x*9 \sqrt{3} } = \sqrt{27*3} = \sqrt{81} =9$