Question

Sa se determine mulțimea ​

Answer 1

6/2x-3=> 2x-3 divide 6

=> 2x-3 e D6

<=> 2x-3 e {-1 , -2 ,-3 ,-6, 1 , 2 , 3,6} | +3

2x e {2; 1 ; 0 ; -3 ; 4 ; 5; 6;9} | :2

x e {1; 0,5 , 0 , -3/2 , 2 , 5/2 , 3 , 4,5}

dar x apartine z => x e { 0,1,2,3 }

Verif. :

6/2x0-3=6/-3=-2 (A)

6/2x1-3=6/-1 = -6 (A)

6/2x2-3= 6/4-3=6/1 = 6 (A)

6/2x3-3=6/6-3=6/3= 2 (A)

( ͡° ͜ʖ ͡°)

( ͡° ͜ʖ ͡°)

Answer 2

Răspuns:

Explicație pas cu pas:

(2x-3) ∈ D₆

D₆ = { +1;-1;+2;-2;+3;-3}

2x-3 =1

x=2

2x-3= -1

x=1

2x-3=2

x=5/2 care ∉Z

2x-3 = -2

x=1/2  care ∉Z

2x-3= 3

x=3

2x-3= -3

x=0

A= {0;1;2;3}

Succes !!