Question

sa se determine numerele a si b, stiind ca a/11 = b/3 si: a) a + b = 56 ; b) a - b = 0,8 ; c) 3a + b = 36
URGENT ​

Answer 1

Răspuns:

a/11=b/3=>3a=11b=>a=11b/3

Inlocium si obținem :

11b/3+b=56

Aducem la același numitor :

11b+3b=56

14b=168

b=168:14

b=12

a+12=56=>a=56-12=>a=44

B)

11b/3-b=8/10

33b-30b=24

3b=24

b=24:3

b=8

a-8=0,8

a=8,8

C)

3a+b=36

3*11b/3+b=36

33b+3b=108

36b=108

b=108:36

b=3

3a+3=36

3a=36-3

3a=33

a=11