Question

Sa  se determine numerele naturale x,y,z direct proportionale cu nr 2,5,8 sic2x+4y+7z=1988 rezolvare completa

Answer 1

x,y,z  dp cu 2,5,8

x/2=y/5=z/8=k
x=2k
y=5k
z=8k

2x+4y+7z=1988
2*2k+4*5k+7*8k=1988
4k+20k+56k=1988
80k=1988
k=24,85

x=2*24,85=49,7
y=5*24,85=124,25
z=8*24,85=198,8