Question

Sa se determine perechile de numere naturale(a,b) care verifica relatia :
408-[1520:8-3x(2+2a+3b)]x2=130
Imi trebuie repede va rog 

Answer 1

408-[1520:8-3x(2+2a+3b)]x2=130

408-[190-3x(2+2a+3b)]x2=130

[190-3x(2+2a+3b)]x2=408-130

[190-3x(2+2a+3b)]x2=278

190-3x(2+2a+3b)=278:2

190-3x(2+2a+3b)=139

3x(2+2a+3b)=190-139

3x(2+2a+3b)=51

2+2a+3b=51:3

2+2a+3b=17

2a+3b=15

singurele perchi d enumere sunt a=0 b=5
a=3 b=3
a=6 b=1