Question

Sa se determine trei numere naturale a, b, c stiind ca:
a:b=3; c:b=5 rest 19; a+b+c=1.000
Va rog ajutatima.

Answer 1

a+b+c=1000 a:b=3; => a=3b; c:b= 5 rest 19; =>c=5b+19; Inlocuim: 3b+b+5b+19=1000; 9b=1000-19=981; b=981:9=109;=>a=3×109=327; c=5×109+19=545+19=564

Answer 2

a:b=3⇒a=3b
c:b=5 rest 19⇒c=5b+19
a+b+c=1000
3b+b+5b+19=1000
9b=1000-19
9b=981⇒b=981:9⇒b=109
a=3b=3·109=327⇒a=327
c=5b+19=5×109+19=545+19=564⇒c=564