Question

Sa se determine x apartine lui R,astfel incat 8^x=4 pe langa x/2+1

Answer 1

$8^x=(2^3)^x= 2^{3x } \\ 4^{ \frac{x}{2}+1 } =( 2^2)^{ \frac{x}{2}+1 } = 2^{x+2} \\ 8^x= 4^{ \frac{x}{2}+1 } ; 2^{3x}= 2^{x+2} \\ 3x=x+2 \\ 2x=2 \\ x=1$

Answer 2

8^x= 4^(x+1/2)
(2³)^x= 2² ^(x+1/2)
2^3x=2^(2x+1)
2=2
3x=2x+1
x=1
verificare
8^1=4^(3/2)=√4³=√64=8, adevarat , problema e bine rezol;vata