Question

Sa se determine x∈R din proportia: x+3/2∛3=∛9/8+x
/-supra

Answer 1

(x+3) / 2∛3 =  ∛9/(8+x)

Inmultim pe diagonala:

(x+3)(x+8)=2*∛3*∛9

x²+3x+8x+24= 2 * ∛27

x²+11x+24= 2 * 3

x²+11x+24=6

x²+11x+18=0

Δ=121-4*18= 121-72=49 ⇒√Δ=7

x₁= (-11+7)/2= - 4/2= -2

x₂=(-11-7)/2= -18/2= -9

S:x∈{-2,-9}