Question

Sa se determine x si y astfel incat : $3x^2+5y^2+2 \sqrt{3}x+2 \sqrt{5}y =-2$

Answer 1

3x²+2√3x+1+5y²+2√5y+1=0
(√3x+1)²+(√5y+1)²=0
x√3+1=0
x=-1/√3=-√3/3
y√5+1=0
y=-1/√5=-√5/5

x=-√3/3
y=-√5/5