Question

sa se discute natura si semnele radacinilor ecuatiei x2-4x+m+2=0

Answer 1

[tex]x^2-4x+m+2=0\\ \triangle=b^2-4ac=16-4(m+2)=8-4m=0=\ \textgreater \ m= 2\\ Cazul\ I)m \neq 2=\ \textgreater \ ecuatia\ are\ doua\ radacini\ reale\ distincte\\ S=-b/a=4=\ \textgreater \ ambele\ radacini \ sunt\ simultan \ \ \textgreater \ 0\ sau \ \textless \ 0\\ P=c/a=m+2\\ Cazul\ II)m=2 =\ \textgreater \ ecuatia\ are \ x_1=x_2=-b/a=4[/tex]