Question

Sa se efectueze:
1. (5^6×5^7)^3:5^37+(7^8)^9:7^71+1^2018=?
2.
[(2^3)^4]^5:2^59+(7^3)^0-572^0+0=?
3.
(2^700+2^700):2^699+(3^600+3^600+3^600):3^599=?
4.
{[(7^2)^3]^4}^0+(5^9)^4:(5^4)^9-2018=?

Answer 1

α= (5¹³)³ ÷ 5³⁷ + 7⁷² ÷ 7⁷¹ + 1 =

= 5³⁹ ÷ 5³⁷ + 7⁷² ÷ 7⁷¹+ 1=

= 5²+ 7+1= 25+7+1=
32+1= 33

b)= 2⁶⁰ ÷ 2⁵⁹ + 1−1+0=

= 2+1−1+0= 3−1+0=
2+0= 2

C)= 2⁷⁰⁰ ×(1+1) ÷2⁶⁹⁹+3⁶⁰⁰×(1+1+1) ÷ 3⁵⁹⁹=

= 2⁷⁰⁰ × 2 ÷2⁶⁹⁹ + 3⁶⁰⁰× 3 ÷ 3⁵⁹⁹=

= 2⁷⁰¹ ÷2⁶⁹⁹ + 3⁶⁰¹ ÷ 3⁵⁹⁹ =

= 2²+ 3²= 4+9= 13

D)= 1+5³⁶÷5³⁶− 2018⁰=

= 1+1−1= 1