Question

sa se formuleze ecuatia de gradul 2 , daca
a. x1= 2 x2= -3

Answer 1

   
[tex]\displaystyle\\ \text{Metoda 1:}\\ (x - x_1)(x-x_2)=0\\ (x - 2)(x-(-3))=0\\ (x - 2)(x+3)=0\\ x^2 -2x +3x-6\\ \boxed{x^2+x-6=0} \\\\ \text{Metoda 2 (cu relatiile lui Viete):}\\ x^2 -Sx+P=0\\ S=x_1+x_2=2-3=-1\\ P=x_1x_2=2\cdot(-3)=-6\\ x^2 -(-1)x+(-6)=0\\ x^2 +1x-6=0\\ \boxed{x^2 +x-6=0} [/tex]