Question

sa se gaseasca cinci numere consecutive impare care au suma 155

Answer 1

a+1+a+3+a+5+a+7+a+9 = 155
5a = 155-(1+3+5+7+9)
5a =  155-25
5a = 130
a = 130:5
a = 26
a+1 = 26+1 = 27
a+2 = 26+3 = 29
a+5 = 26+5 = 31
a+7 = 26+7 = 33
a+9 = 26+9 = 35

I--I+1
I--I+3
I--I+5
I--I+7
I--I+9     }155
egalam segmentele
155-(1+3+5+7+9) = 155-25 = 130
aflam cat reprezinta un segment
130:5 = 26
dupa care aflii fiecare nr