Question

sa se imparta 100 in parti direct proportionale cu 2;3;5

Answer 1

a+b+c=100
a/2=b/3=c/5
a/2+b/3+c/5=a+b+c/2+3+5=100/10=10

a/2=10. a=2*10=20
b/3=10. b=3*10=30
c/5=10. c=5*10=50

verificare: 20+30+50=100

Answer 2

notam cu :
x-primul nr
y- al 2 lea nr
z- al 3 lea nr

x+y+z=100

x,y,z d.p 2 ,3,5
x/2=y/3=z/5=k
x/2=k=>x=2k
y/3=k=> y=3k
z/5=k=>z=5k

2k+3k+5k=100
10k=100
k=100:10
k=10

x=2·10=20
y=3·10=30
z=5·10=50