Question

Sa se imparta 235/12 in parti direct proportionale cu numerele 4/3,5/6,1,3/4

Answer 1

4k/3+5k/6+1k+3k/4 = 235/12   numitor comun 12
4k*4 + 5k*2 1k*12+ 3k*3 = 235
16k+10k+12k+9k=235
47k=235
k=5

Asadar, numarul 235/12 poate fi impartit in 
4k/3 = 4*5/3 = 20/3
5k/6 = 5*5/6 = 25/6
1k=1*5=5
3k/4 = 3*5/4 = 15/4

Answer 2

a/4/3=b/5/6=c/1=d/3/4=k 
a/4/3=k => 3a/4=k =>3a=4k  => a=4k/3
b/5/6=k => 6b/5=k => 6b=5k => b=5k/6
c/1=k => c=k
d/3/4=k => 4d/3=k => 4d=3k => d=3k/4
a+b+c=235/12
4k/3+5k/6+k+3k/4=235/12  |*12
16k+10k+12k+9k=235
47k=235
k=235/47
k=5

a=4k/3 => a=4*5/3 => a=20/3
b=5k/6 => b=5*5/6 => b=25/6
c=k => c=5
d=3k/4 => d=3*5/4 => d=15/4