Question

sa se imparta nr 625 in parti direct proportionale cu nr:0,2;0,3;0,(3)
sa se afle nr x,y,z si t a caror suma este 70 si sunt invers proportionale cu nr:0,(3);0,5;0,2 si 0,25
ajutor cat mai rapid posibil!!!!!!

Answer 1

a+b+c=625
a=0,2k=k/5
b=0,3k=3k/10
c=0,(3)k=3k/9=k/3
k/5+3k/10+k/3=625
6k+9k+10k=18750
25k=18750
k=750
a=k/5=750/5=150
b=3k/10=3*750/10=225
c=k/3=750/3=250

x+y+z+t=70
x/[1/0,(3)]=k    x=3k
y/(1/0,5)=k      y=2k
z/(1/0,2)=k      z=5k
t/(1/0,25)=k    t=4k 
3k+2k+5k+4k=70
14k=70
k=5
x=3*5=15
y=2*5=10
z=5*5=25
t=4*5=20