Question

Sa se imparta numarul 301 in 3 parti invers proportionale cu numerele 12 ,10 si 18

Answer 1

a/(1/12)=k    12a=k   a=k/12
b/(1/10)=k    10b=k   b=k/10
c/(1/18)=k    18c=k   c=k/18

a+b+c=301
k/12+k/10k+k/18=301
15k+18k+10k=5418
43k=54180
k=1260
a=1260/12=105
b=1260/10=126
a=1260/18=70