Question

Sa se imparta numarul 5724 in parti direct proportionale cu numerele 12;19 si 22.​

Answer 1

a+b+c=5724

{a,b,c} d.p {12,19,22}

a/12=b/19=c/22=k

a=12k

b=19k

c=22k

k=5724/53=108

a=1296

b=2052

c=2376