Question

Sa se imparta numarul 7 in parti invers proportionale cu 2,3 ; 0,5 ; 0,(3)

Answer 1

a+b+c=7
a*2,3=b*0,5=c*0,(3)=k
a=$\frac{10k}{23}$
b=$\frac{10k}{5}$
c=3k
50k+230k+345k=7*115
625k=805
k=1,288
a=0,56
b=2,576
c=3,864