Question

Sa se imparta numarul 80 in parti dirsct proportionale cu 0,(3); 1,2(6) ;1,8(3)

Answer 1

0,(3)=3/9=1/3
1,2(6)=(126-12)/90=114/90=19/15
1,8(3)=(183-18)=165/90=11/6

a/(1/3)=b/(19/15)=c/(11/6)
3a=15b/19=6c/11
b=57a/15=19a/5
c=33a/6=11a/2
a+19a/5+11a/2=80
10+38a+55a=800
103a=800
a=800/103
b=19/5×800/103=3040/103
c=11/2×800/103=4400/103

verificare 800/103+3040/103+4400/103=8240/103=80