Question

Sa se introduca sub radical
-2√5, 4(radical de ordin 3)√3, -3(radical de ordin 3) √4, 2(radical ordin 3) √1\4, -1\2(radical ordin 3) √-1\3, 2\3ori(radical ordin 3)√27\8.

Answer 1

-2√5 = - √5×2² = -√20
4∛3 = ∛4³×3 = ∛192
-3∛4 = -∛4×3³ = -∛4×27 = -∛108
2∛(1/4) = ∛2³×(1/4) = ∛2³ ×1/2² =∛2
 -1\2(radical ordin 3) √-1\3 poti sa-l mai scrii odata, cu paranteze? Nu-mi dau seama daca radicalul este la numitor sau la numarator...
2/3 × ∛27/8 = ∛(27/8) × (2³/3³) = ∛(27/8) × 8/27 = ∛1=1