Question

SA se logaritmeze expresiile :
8 radical de ordin 3 din 4 a la puterea a 2a b la puterea a 3a

Answer 1

$8 \sqrt[3]{4a^2b^3}| ln \ \textless \ =\ \textgreater \ lnE=ln( 8 \sqrt[3]{4a^2b^3})=ln[8*(4a^2b^{3})^ \frac{1}{3} ]=ln8+ \frac{1}{3}ln4+$+$\frac{2}{3} lna+ \frac{3}{3}lnb= 3ln2+ \frac{2}{3} ln2+ \frac{2}{3} lna+lnb$