Question

Sa se reprezinte sub forma trigonometrica numarul : z=6+4i

Answer 1

$z = 6 + 4i \\ r = \sqrt{{6}^{2} + {4}^{2} } \\ 0 = arctan( \frac{4}{6} ) \\ r = 2 \sqrt{13} \\ 0 = arctan( \frac{2}{3} ) \\ z = 2 \sqrt{13} ( \cos(arctan( \frac{2}{3} )) + i \times \sin(arctan( \frac{2}{3} )))$