Question

Sa se rezolve: (2x+1)la patrat = (x-2)la patrat

Answer 1

$(2x+1)^2=(x-2)^2 <=> 4x^2+4x+1=x^2-4x+4 <=> \\ 3x^2+8x-3=0\\delta=64+4*9=100=10^2\\x_{1}= \frac{-8+\sqrt{100}}{6} =\frac{-8+10}{6} = \frac{1}{3} \\x_{2}=\frac{-8-\sqrt{100}}{6} = \frac{-8-10}{6}=-3$