Question

Sa se rezolve ecuatia : 4^x+2*2^x=2​

Answer 1

Răspuns:

4^x=2^2x

2^2x+2*2^x=2

2^2x+2*2^x-2=0

t=2^x

t^2+2t-2=0

a=1

b=2

c=-2

Delta=4-(-8)=4+8=12

t1=-2+2√3/2=(-4+2√3)/2

t2=-2-2√3/2=(-4-2√3)/2

2^x=(-4-2√3)/2

log 2(-4-2√3)/2=x