Question

Sa se rezolve ecuatia:

$log_{2} 2x + log_{2x} 2=2$

Answer 1

$log_{2}2x=t \\ t+ \frac{1}{t}=2 \\ t^2-2t+1=0 \\ (t-1)^2=0 \\ t=1$
revenim la substitutie
$log_{2}2x=1; log_{2}2x= log_{2}2; 2x=2;x=1$