Question

sa se rezolve ecuatia

$\sqrt{3} + 2sinx = 0$

Answer 1

2sinx=-√3
sinx=-√3/2
x=kπ+(-1)^k*arcsin(-√3/2)
x=kπ+(-1)^k* (-π/3)
x=kπ+ (-1)^(k+1)*(π/3)