Question

Să se rezolve ecuatiile :

Answer 1

x=log (8) 16

2^x=16
2^x=2^4
x=4

(1/3)^x=1
(1/3)^x= (1/3)^0
x=0

4^x=1/16
4^x=1/4^2
4^x=4^(-2)
x=-2

10^x=(3)V10^3=10^1
x=1

j. 5^x=1/(3)V5^2
5^x=1/5^(2/3)=5^(-2/3)
x= -2/3

k. (4/5)^x=5^2/4^2=1/(4/5)^2=(4/5)^(-2)
     x= -2

m. 3^(-1-x)=3^-(2x-3)=3^(-2x-3)
      - 1 - x= - 2x - 3
       2x-x= 1 -3
        x=-2