Question

sa se rezolve ecuatiile:
a)log din baza 4(3-2x)=1/2

Answer 1

$\displaystyle log_4(3-2x)= \frac{1}{2} \\ 3-2x \ \textgreater \ 0 \Rightarrow x \ \textless \ \frac{3}{2} \\ log_4(3-2x)= \frac{1}{2} \Rightarrow log_4(3-2x)=log_4 \sqrt{4} \\ 3-2x= \sqrt{4} \\ 3-2x=2 \\ -2x=2-3 \\ -2x=-1 \\ \boxed{x= \frac{1}{2} }$