Question

Sa se rezolve exercitiile date(Combinatorica)

Answer 1

$a) T_{k+1}= C^k_{9} * x^{9-k}* (\frac{1}{2} y)^{k} \\ x^{9-k}=x^6 \\ 9-k=6 \\ k=3 \\ T_{3+1}= C^3_{9}x^6*(1/2y)3=84x^6* \frac{1}{8}y^3= \frac{21}{2}x^6y^3$
[tex]b) T_{k+1}= C^k_{13}* ( a^{ \frac{1}{2} }) ^{13-k} * (a^{- \frac{1}{3} })^k \\ \frac{13-k}{2}- \frac{k}{3}=4 \\ 39-3k-2k=24 \\ -5k=-15;k=3 \\ T_{3+1}=contine:a^4 [/tex]

Answer 2

am facut si una comuna cu Jopel fara sa imi dau seama..ne-a dat la fel
n-am facut chiar toate calculele sau eventualele simplificari