Question

Sa se rezolve functia f:R⇒R ,f(x) =x la 2 -11x+30 .Sa se calculeze f (0) ,f(1)·...·f(6). Urgent!!!

Answer 1

f(0)=0²-11*0+30=30
f(1)=20
f(2)=12
f(3)=5
f(4)=2
f(5)=7
f(6)=28

Answer 2

$f:R$⇒$R$$,f(x)= x^{2} -11x+30$
[tex]f(0)*f(1)*...*f(6)=? [/tex]
$f(1)= 1^{2} -11*1+30=1-11+30=-10+30=20$
$f(2)= 2^{2} -11*2+30=4-22+30=12$
$f(3)= 3^{2} -11*3+30=9-33+30=6$
$f(4)= 4^{2} -11*4+30=16-44+30=2$
$f(5)= 5^{2} -11*5+30=25-55+30=0$
$f(6)= 6^{2} -11*6+30=36-66+30=0$
$f(1)*f(2)*...*f(6)=20*12*...*0=0$