Question

Să se rezolve functiile

Answer 1

Mult succes în continuare !

Answer 2

$a) \sqrt{x - 5} = 2 \\ \\ { \sqrt{x - 5} }^{2} = {2}^{2} \\ \\ x - 5 = 4 \\ \\ x - 5 + 5 = 4 + 5 \\ \\ x = 4 + 5 \\ \\ x = 9 \\ \\ \sqrt{9 - 5} = 2 \\ \\ 2 = 2 \\ \\ x = 9$

$b) \sqrt{3x + 4} = 5 \\ \\ { \sqrt{3x + 4} }^{2} = {5}^{2} \\ \\ 3x + 4 = 25 \\ \\ 3x + 4 - 4 = 25 - 4 \\ \\ 3x = 25 - 4 \\ \\ 3x = 21 \\ \\ 3x : 3 = 21 : 3 \\ \\ x = 7 \\ \\ \sqrt{3 \times 7 + 4} = 5 \\ \\ 5 = 5 \\ \\ x = 7$

$c) \sqrt{4x - 3} = 7 \\ \\ { \sqrt{4x - 3} }^{2} = {7}^{2} \\ \\ 4x - 3 = 49 \\ \\ 4x - 3 + 3 = 49 + 3 \\ \\ 4x = 49 + 3 \\ \\ 4x = 52 \\ \\ 4x : 4 = 52 : 4 \\ \\ x = 13 \\ \\ \sqrt{4 \times 13 - 3} = 7 \\ \\ 7 = 7 \\ \\ x = 13$

$d) \sqrt{x + 4} = \sqrt{2x - 3} \\ \\ { \sqrt{x + 4} }^{2} = { \sqrt{2x - 3} }^{2} \\ \\ x + 4 = 2x - 3 \\ \\ x - 2x = - 3 - 4 \\ \\ - x = - 7 \\ \\ - 1 \times ( - x) = - 1 \times ( - 7) \\ \\ x = 7 \\ \\ \sqrt{7 + 4} = \sqrt{2 \times 7 - 3} \\ \\ 3,31662 = 3,31662 \\ \\ x = 7$

$e) \sqrt{5x - 2} = \sqrt{x + 4} \\ \\ { \sqrt{5x - 2} }^{2} = { \sqrt{x + 4} }^{2} \\ \\ 5x - 2 = x + 4 \\ \\ 5x - x = 4 + 2 \\ \\ 4x = 6 \\ \\ 4x : 4 = 6 \div 4 \\ \\ x = 6 : 4 = \frac{6}{4} ^{(2} = \frac{3}{2} \\ \\ \sqrt{5 \times \frac{3}{2} - 2 } = \sqrt{ \frac{3}{2} + 4 } \\ \\ 2,34521 = 2,34521 \\ \\ x = \frac{3}{2}$

$f) \sqrt{4x - 1} = \sqrt{3x + 3} \\ \\ { \sqrt{4x - 1} }^{2} = { \sqrt{3x + 3} }^{2} \\ \\ 4x - 1 = 3x + 3 \\ \\ 4x - 3x = 3 + 1 \\ \\ x = 4 \\ \\ \sqrt{4 \times 4 - 1} = \sqrt{3 \times 4 + 3} \\ \\ 3,87298 = 3,87298 \\ \\ x = 4$