Question

sa se rezolve in c ecuatia (2-5i)z=2+5i

Answer 1

$z= \frac{2+5i}{2-5i} \\ z= \frac{(2+5i)^2}{2^2+5^2} \\ z= \frac{4+20i-25}{29} \\ z= \frac{-21+20i}{29}$