Question

Sa se rezolve in multimea numerelor rationale ecuatiile:

a) x+3 supra 2= 1 supra 4

b) x: 2,5= - 3,4

c) -9x+3,2= 2 ori (x-5)

Answer 1

$a) \frac{x + 3}{2} = \frac{1}{4} \\ \frac{2x + 6}{4} = \frac{1}{4} \\ 2x + 6 = 1 \\ 2x = 1 - 6 \\ 2x = - 5 \\ x = - \frac{5}{2} = 2,5$

Answer 2

1) x+3/2=1/4 ===)) x=1/4-3/2
X= 2-4/8= -3/4
2) x:2,5= -3,4 ===)) x= -3,4inmultit cu 2,5= -661