Question

Sa se rezolve in r ecuatia
$\frac{1}{x+1} + \frac{1}{x-1} = \frac{4}{x^2-1}$

Answer 1

1/x+1 + 1/x-1=4/xla 2 -1 =n.c 

x-1/ x la 2+x-x-1  + x+1 /x la 2 -x+x-1 =4/xla 2 -1 ======================
2/x la 2 -1 = 4/x2-1   
2(x la 2-1)=4(x la 2 -1 )
2 x la 2 -2 =4 x la a 2 -4 
2 x la 2 -4 x la 2 = -4 + 2 
2x(x-2x)=-2
a) x1 = 0
b)x-2x = -2 
-x =-2 
x= 2 
cam asa sper ca team ajutat 
minus cu minus e + 

Answer 2

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