Question

Sa se rezolve in R inecuatiile:
a) x-3(x+2) <egal -2x+5(x+1)
b) (x+1) la put 2 - (x-1) la put 2 >egal 2x+4​

Answer 1

$[tex]x - 3(x + 2) \leqslant - 2x + 5(x + 1) \\ x - 3x - 6 \leqslant - 2x + 5x + 5 \\ - 2x - 6 \leqslant 3x + 5 \\ - 2x - 3x \leqslant 5 + 6 \\ - 5x \leqslant 11 \\ x \leqslant \frac{11}{5} </p><p>$

$( {x + 1})^{2} - ( {x - 1})^{2} \geqslant 2x + 4 \\ {x}^{2} + 2x + 1 - {x}^{2} + 2x - 1 \geqslant 2x + 4 \\ 4x \geqslant 2x + 4 \\ 4x - 2x \geqslant 4 \\ 2x \geqslant 4 \\ x \geqslant 2$

la prima trb sa scrii ca x apartine{ ....,11/5}

la a doua trb sa scrii ca x apartine{ 2,3,4....}