Question

Sa se rezolve in RxR sistemul de ecuatii$\left \{ {{x-y=-4} \atop {xy=3}} \right.$

Answer 1

x=y-4

y(y-4)=3

y²-4y-3=0

Δ=16+12=28

y1=(4-2√7)/2=2-√7

y2=(4+2√7)/2=2+√7

atunci

x1=2-√7-4=-2-√7

x2=2+√7-4=√7-2