Question

Să se rezolve în Z ecuațiile: a) 2x+3=-7; b) 9-2x=-31-7x; d) 3(x-1)=-6; e) 3(x+1)=11-x; g) 2(x+2)=3x-6; h) 4x+2=3(x+1); j) 8x-16=0; k) 5+x-2=x+3; m) 4x+2=30; n) 2(x+1)=10-x; c) 7-2x=23-12x; f) 1-4(2x-1)=3(x+2)+10; i) 3-5(2x-1)= 4(x+2)+14; 1) [x+1=3; 0) 2+|x—3=7.​

Answer 1

a) 2x+3=-7;

2x=-10

x=-5

b) 9-2x=-31-7x;

-2x+7x=-31-9

5x=-40

x=-8

d) 3(x-1)=-6;

3x-3=-6

3x=-3

x=-1

e) 3(x+1)=11-x;

3x+3=11-x

3x+x=11-3

4x=8

x=2

g) 2(x+2)=3x-6;

2x+4=3x-6

2x-3x=-6-4

-x=-10

x=10

h) 4x+2=3(x+1);

4x+2=3x+3

4x-3x=3-2

x=1

j) 8x-16=0;

8x=16

x=2

k) 5+x-2=x+3;

0=0=> x€Z

m) 4x+2=30;

4x=28

x=7

n) 2(x+1)=10-x;

2x+2=10-x

2x+x=10-2

3x=8

x=8/3 diferit de Z deci x= mulțimea vida

c) 7-2x=-23-12x;

-2x+12x=-23-7

10x=-30

x=-3

f) 1-4(2x-1)=3(x+2)+10;

1-8x+4=3x+6+10

-8x-3x=16-1-4

-11x=11

x=-1

i) 3-5(2x-1)= 4(x+2)+14;

3-10x+5=4x+8+14

-10x-4x=14+8-3-5

-14x=14

x=-1

l) |x+1|=3;

x+1=3 sau x+1=-3

x=2 sau x=-4

0) 2+|x—3|=7.

|x-3|=5

x-3=5 sau x-3=-5

x=8 sau x=-2