Question

sa se rezolve inecuatiile, in multimea numerelor naturale: 3x<12, 2+3x<8, 9-2x>5. dau coroana

Answer 1

3x < 12
x < 12 : 3
x < 4
S = {0,1,2,3}

2 + 3x < 8
3x < 8 - 2
3x < 6
x < 6 : 3
x < 2
S = {0,1}

9 - 2x > 5
2x < 9 - 5
2x < 4
x < 4 : 2
x < 2
S = {0,1}

Answer 2

3x<12
x<12:3
x<4
S={0,1,2,3}

2+3x<8
3x<8-2
3x<6
x<6:3
x<2
S={0,1}

9-2x>5
2x<9-5
2x<4
x<4:2
x<2
S={0,1}