Question

Sa se rezolve ... radical de ordin 6 din (x la puterea 2 -2x+1) = radical de ordin 3 din (3-x)

Answer 1

$\sqrt[6]{x^2-2x+1} = \sqrt[3]{3-x} \\ \\ \sqrt[6]{(x-1)^2} = \sqrt[3]{3-x} \\ \\ \sqrt[3]{x-1} = \sqrt[3]{3-x}~~~~ |^3 \\ \\ x-1=3-x \\ \\ 2x=4 \\ \\ x=2$