Question

Sa se rezolve sistemul de ecuatii: x-1=y si x^2+2x-3=y

Answer 1

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Answer 2

x-1=y ;

x² +2x-3=y => x² +2x+1-4=y <=> (x+1)² -4=y <=> (x+1-2)·(x+1+2)=y <=> (x-1)·(x+3)=y dar deoarece x-1=y => x+3=1 <=> x=-2 de unde y=-3 sau x-1=y=0 => x=1 si y=0 .

S={(-2;-3),(1;0)} .