Question

Sa se rezolve sistemul in C si sa se puna conditiile de existenta:

Answer 1

|x-1|=y-5 si introducem in prima ecuatie

y-5+|y-5|=6

daca y<5 atunci |y-5|=5-y =>y-5+5-y=0 diferit de 6, deci S=∅

daca y≥5 atunci |y-5|=y-5 => y-5+y-5=2y-10=6 => y=8 (∈[5,∞)) => |x-1|=3 =>x∈{-2,4}

deci S={{-2,8};{4,8}}