Question

Sa se rezolve [x]=3;[x+2]=-3;[2x]=2;[3x+1 supra 2] =5

Answer 1

3≤x<4...x∈[3;4)


-3≤x+2<-2
 -3-2≤x+2-2<-2-2
-5≤x<-4  x∈[-5;-4)

2≤2x<3
1≤x<3/2  x∈[1,3/2)

5≤(3x+1)/2<6
10≤3x+1<12
9≤3x<11
 3≤x<11/3  x∈[3, 11/3)