Question

Sa se rezolveze ecuatia: Ix+1I+I2x+2I=3

Answer 1

|x+1|+|2x+2|=3
|x+1|+|2(x+1)|=3
|x+1|+2|x+1|=3
3|x+1|=3
|x+1|=1
a) x+1= 1 ⇒ x₁=0
    x+1= -1⇒ x₂=-2
S:x∈{0,-2}

Answer 2

ambele module sunt pozitive deci inlaturam modulul.Sau avem x+1=-1 => x=-2 Vom avea x+1 +2x+2 =3 => 3x+3 =3=> x=0
am folosit urmatoarea proprietate:
|a|= +sau - a. => x = -2 sau 0