Question

Să se scrie primii patru termeni ai progresiei geometrice (bn)≥1, dacă b1=-10 iar q=1pe2 ;

Answer 1

b2=b1·q¹=-10·1/2=-5
b3=b2·q=-5·1/2=-5/2
b4=b3·q=-5/2·1/2=-5/4
b5=b4·q=-5/4·1/2=-5/8

Answer 2

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b₁ = –10


b₂ = b₁ • q = –10 • 1 / 2 = —10 / 2 = –5


b₃ = b₂ • q = –5 • 1 / 2 = —5 / 2 = –2,5


b₄ = b₃ • q = –2,5 • 1 / 2 = —2,5 / 2 = –1,25



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