Question

Sa se simplifice fractiile pana devin ireductibile: 6 supra 27, 7 supra 35, 42 supra 51,56 supra 35

Answer 1

6/27 = 2/9

7/35 = 1/5

42/51 = 14/17

56/35 = 8/5

Answer 2

6/27 =( 6 : 3 ) / ( 27 : 3 ) =  2/9
  → simplific atat numaratorul cat si numitorul cu 3

7/35 = ( 7 : 7 ) / ( 35 : 7 ) =  1/5
  → simplific fractia cu 7

42/51 =(42 : 3 ) / ( 51 : 3) = 14/17
  → simplific fractia cu 3

56/35 =( 56 : 7 ) / ( 35 : 7 ) = 8/5= 1 intreg si 3/5
  → simplific fractia cu 7