Question

Sa se simplifice, pana devin fractii inductibile: a 10/6 b 30/45 c 35/49 d 121212/151515​

Answer 1

Răspuns: Ai rezolvarea mai jos

Explicație pas cu pas:

Salutare!

$\mathbf{a)~\dfrac{10}{6}^{(2}=\dfrac{5}{3}\longrightarrow ~fractie~ireductibila }$

$\it~$

$\mathbf{b)~\dfrac{30}{45}^{(15}=\dfrac{2}{3}\longrightarrow ~fractie~ireductibila }$

$\it~~$

$\mathbf{c)~\dfrac{35}{49}^{(7}=\dfrac{5}{7}\longrightarrow ~fractie~ireductibila }$

$\it~~$

$\mathbf{d)~\dfrac{121212}{151515}^{(9}=\dfrac{13468}{16835}^{(7}=\dfrac{1924}{2405}^{(13}=\dfrac{148}{185}^{(37}=\dfrac{4}{5}\longrightarrow~fractie~ireductibila}$

$\it~~$

PS: Daca esti pe telefon, te rog sa glisezi spre dreapta pentru a vedea rezolvarea completa

Bafta !

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