Question

Salut!Ajutatima rapid!!Pls.Ex.(4).

Answer 1

Stiind ca m(∠A) = 90° ⇒ m(∠B)+m(∠C)+m(∠D) = 360°-90° = 270°

(∠B; ∠C; ∠D)  d.p.  (5;6;7) ⇒ 

⇒ $\frac{B}{5}= \frac{C}{6} = \frac{D}{7} = \frac{B+C+D}{5+6+7} = \frac{270}{18} = 15$ ⇒

m(∠B) = 15*5 ⇒m(∠B) = 75°
m(∠C) = 15*6 ⇒m(∠C) = 90°
m(∠D) = 15*7 ⇒ m(∠D) = 105°