Question

Salut, am de rezolvat o ecuatie de gradul 3, iata ce am primit eu, dupa Schema lui Horner, din pacate am primit si cu rest, ceea ce imi si impiedica sa rezolv ecuatia:
x^3-6x^2+3x+10=0, (x-1) (x^2-5x-2)+8=0, ma puteti ajuta?

Answer 1

a) x×3-6x×2+3x+10=0
3x-12x+3x+10=0
-11x+10=0
-11x=-10/×(-1`)
11x=10
x=10/11

b)(x-1)(x×2-5x-2)+8=0
(x-1)(2x-5x-2)+8=0
2x²-5x²-2x-2x+5x+2+8=0
-3x²+x+10=0
Δ=b²-4ac=1²-4·(-3)×10=1+121=121
x'=-b-√Δ/2a=-1-√121/-6=-1-11/-6=-2
x''=-b+√Δ/2a=-1+11/-6=10/-6=5/-2