Question

Salut, am la matematica o probelma mai ciudata. Se afla in atasament. Problema 2

Answer 1

   
[tex]\displaystyle\\ 2^{-1}\cdot2^2: \sqrt{4} = \frac{1}{2} \cdot 4 : 2 = \frac{4}{2} : 2 = 2:2 = \boxed{\bf 1}\\\\ \Longrightarrow~~\Delta ABC \text{ este congruent cu } \Delta A'B'C'\\\\ \Longrightarrow~~\boxed{\bf \Delta ABC \equiv \Delta A'B'C' }[/tex]